Mathematics 9 (Complete Solutions)

# Q3 Find

If
A =

 -1 2 2 1

,
B =

 1 -1

,
C =

 1 -1 2

,
D =

 1 2 3 -1 0 2

, then find ,

(i) A +

 1 1 1 1

(ii) B +

 -2 3

(iii) C +

 -2 1 3

(iv) D +

 0 1 0 -2 0 1

(v) 2A
(vi) (-1)B
(vii) (-2)C
(viii) 3D
(ix) 3C

Solution:

(i) A +

 1 1 1 1

Putting A =

 -1 2 2 1

=

 -1 2 2 1

+

 1 1 1 1

=

 -1+1 2+1 2+1 1+1

=

 0 3 3 2

(ii) B +

 -2 3

Putting B =

 1 -1

=

 1 -1

+

 -2 3

=

 1-2 -1+3

=

 -1 2

(iii) C +

 -2 1 3

Putting C =

 1 -1 2

=

 1 -1 2

+

 -2 1 3

=

 1-2 -1+1 2+3

=

 -1 0 5

(iv) D +

 0 1 0 2 0 1

Putting D =

 1 2 3 -1 0 2

=

 1 2 3 -1 0 2

+

 0 1 0 2 0 1

=

 1+0 2+1 3+0 -1+2 0+0 2+1

=

 1 3 3 1 0 3

(v) 2A

Putting A =

 -1 2 2 1

= 2

 -1 2 2 1

=

 2(-1) 2(2) 2(2) 2(1)

=

 -2 4 4 2

(vi) (-1)B

Putting B =

 1 -1

= -1

 1 -1

=

 -1(1) -1(-1)

=

 -1 1

(vii) (-2)C

Putting C =

 1 -1 2

= -2

 1 -1 2

=

 -2(1) -2(-1) -2(2)

=

 -2 2 -4

(viii) 3D

Putting D =

 1 2 3 -1 0 2

= 3

 1 2 3 -1 0 2

=

 (3)1 (3)2 (3)3 (3)(-1) (3)0 (3)2

=

 3 6 9 -3 0 6

(ix) 3C

Putting C =

 1 -1 2

= 3

 1 -1 2

=

 3(1) 3(-1) 3(2)

=

 3 -3 6

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