(x - 5)(x - 7)(x + 6)(x + 4) - 504 = 0
Solutions
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[(x - 5)(x + 4)] [(x - 7)(x + 6)] - 504 = 0
(x2 + 4x - 5x - 20) (x2 + 6x - 7x - 42) - 504 = 0
(x2 - x - 20) (x2 - x - 42) - 504 = 0
Let x2 - x = t and Put in the equation
(t - 20)(t - 42) - 504 = 0
t2 - 42t - 20t + 840 - 504 = 0
t2 - 62t + 336 = 0
Using the quadratic formula, we have
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OR |
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By Letting t = x2 - x, Putting the value of t, we get
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x2 - x = 6 |
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x2 - x = 56 |
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x2 - x - 6 = 0 --------------(i) |
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x2 - x - 56 = 0 --------------(ii) |
By Equation (i) x2 - x - 6 = 0
Using the Quadratic formula, we have
By Equation (ii) x2 - x - 56 = 0
Using the Quadratic formula, we have
Hence the Solution Set of given equation is {-7, -2, 3, 8}